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js算 时间差

var time1 = new Date('2012-12-23 12:12:34');var time2 = new Date('2012-12-23 12:15:34');// 计算时间差, 单位是毫秒var minus = Math.abs(time1.getTime() - time2.getTime());console.log('时间相差:' + minus + ' 毫秒!');

var date1=new Date(1980,01,01); //开始时间 var date2=new Date(); //结束时间 //计算出相差天数 var days=Math.floor(date3/(24*3600*1000)) //计算出小时数 var leave1=date3%(24*3600*1000) //计算天数后剩余的毫秒数 var hours=Math.floor...

js求时间差 var date1=new Date(); //开始时间 alert("aa"); var date2=new Date(); //结束时间 var date3=date2.getTime()-date1.getTime() //时间差的毫秒数 //计算出相差天数 var days=Math.floor(date3/(24*3600*1000))

var d1 = new Date("1111/1/1 03:00:00");var d2 = new Date("1111/1/1 17:00:00");var gap = Math.abs(d1-d2)/1000/60/60;console.log(gap);

var date1 = new Date('2013/04/02 18:00')var date2 = new Date('2013/04/02 19:22:21')var s1 = date1.getTime(),s2 = date2.getTime();var total = (s2 - s1)/1000;var day = parseInt(total / (24*60*60));//计算整数天数var afterDay = tot...

//+--------------------------------------------------- //| 求两个时间的天数差 日期格式为 YYYY-MM-dd //+--------------------------------------------------- function daysBetween(DateOne,DateTwo) { var OneMonth = DateOne.substring...

var time1 = "2011-01-01" var time2 = "2011-07-02" var tmpBeginTime = new Date(time1.replace(/-/g, "\/")); //时间转换 var tmpEndTime = new Date(time2.replace(/-/g, "\/")); //时间转换 var sumMinTime = 1000 * 60 * 60 * 24 * (365 /...

获取时间差可以通过把2个时间转换为毫秒,然后互减 判断某个时间段是否包含, 如果判断为true,就把时间差再减去这个时间段时间 你最后那个a在12点内13点什么什么的,不懂 规则固定的话大不了写多几个if

这个主要是计算的问题,没有过多的逻辑。下面是简单的代码实现,仅供参考: var oDate1 = new Date(2015,8,1,0,0,0);var oDate2 = new Date(2015,10,1,0,0,0);var nTime = oDate2.getTime() - oDate1.getTime();var day = Math.floor(nTime/8640...

function getTime2Time($time1, $time2){var time1 = arguments[0], time2 = arguments[1];time1 = Date.parse(time1)/1000;time2 = Date.parse(time2)/1000;var time_ = time1 - time2;return (time_/(3600*24));}document.write(getTime2Time(...

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